Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is
1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.Solution(Linked List):
According to the question: delete a node (except the tail).
O(1).
Code(C++):
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: void deleteNode(ListNode* node) { node->val = node->next->val; node->next = node->next->next; } };
Solution:
Shifting the remaining portion of the giving linked list to left by one node. Take the tail into consideration.
O(n).
Code(C++):
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: void deleteNode(ListNode* node) { ListNode* p1 = node; ListNode* p2 = node->next; while(p2->next != NULL){ p1->val = p2->val; p1 = p2; p2 = p2->next; } p1->val = p2->val; p1->next = NULL; } };
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