Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is
1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.Solution(Linked List):
According to the question: delete a node (except the tail).
O(1).
Code(C++):
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
void deleteNode(ListNode* node) {
node->val = node->next->val;
node->next = node->next->next;
}
};
Solution:
Shifting the remaining portion of the giving linked list to left by one node. Take the tail into consideration.
O(n).
Code(C++):
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
void deleteNode(ListNode* node) {
ListNode* p1 = node;
ListNode* p2 = node->next;
while(p2->next != NULL){
p1->val = p2->val;
p1 = p2;
p2 = p2->next;
}
p1->val = p2->val;
p1->next = NULL;
}
};
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